5.28 Find a value z0 of the standard normal random variable...

5.28 Find a value z0 of the standard normal random variable z such that a. P(z ? z0) = .0401 b. P(?z0 ? z ? z0) = .95 c. P(?z0 ? z ? z0) = .90 d. P(?z0 ? z ? z0) = .8740 e. P(?z0 ? z ? 0) = .2967 f. P(?2 < z < z0) = .9710 g. P(z ? z0) = .5 h. P(z ? z0) = .0057

Transcript

00:01 So now here is a solution of the evok question.

00:09 There are first part, a part, in that p bracket small z is smaller or equal than z0 equal to 0 .0401 which is given in the equation.

00:32 Here by using the jad table corresponding to and and z value.

00:45 Calculate the z value corresponding to the area 0 .0401 that to the left of the normal curve so here we get p z is smaller or equal than minus 1 .75 this value is calculated corresponding to the corresponding area by using the z value 0 .0401 so therefore z z 0 equal to minus 1 .75 now you in b part p bracket minus z zero is smaller or equal than z is smaller or equal to z zero equal to given that 0 .95 noted p a is smaller or equal than z is smaller or equal than b so therefore equal to b is equal to j is smaller or equal than b and minus b bracket p bracket z is smaller or equal then here we can separate it into two part now you by using the now here you can put the value of in this equation p z bracket z is smaller or equal than z 0 minus p bracket z is smaller or equal than minus z zero is equal to 0 .95 so p z is smaller or equal than z zero bracket close minus bracket 1 minus p and z minus z zero equal to 0 .95 to be bracket z bracket is smaller or equal than z zero minus one equal to 0 .095 here we can p is bracket is smaller or equal than z zero equal to 0 .075 -975 by using z table here we can also using the jade table corresponding to the normal curve so here we can get that the z is smaller or equal than 1 .96 equal to 0 .975.

04:18 So that z 0 is equal to 1 .96.

04:25 Now move to the c part of the question.

04:33 P bracket minus z 0 is smaller or equal than z is smaller or equal than z is smaller or equal than z.

04:49 So, 90.

04:53 So noted that here we can also it's divided into by using the formula of a is smaller or equal than z is smaller or equal than b equal to p.

05:07 Z is smaller or equal than b b minus p.

05:13 Z is smaller or equal than a bracket close...

Question

5.28 Find a value z0 of the standard normal random variable z such that a. P(z ? z0) = .0401 b. P(?z0 ? z ? z0) = .95 c. P(?z0 ? z ? z0) = .90 d. P(?z0 ? z ? z0) = .8740 e. P(?z0 ? z ? 0) = .2967 f. P(?2 < z < z0) = .9710 g. P(z ? z0) = .5 h. P(z ? z0) = .0057

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