4 Use the given information to find the P-value. Use a 0.05 significance level to reject the null hypothesis or fail to reject. t 48) The test statistic in a two-tailed test is z = 1.95. A) 0.0512; fail to reject the null hypothesis B) 0.0256; reject the null hypothesis C) 0.0512; reject the null hypothesis D) 0.9744; fail to reject the null hypothesis 49) The test statistic in a left-tailed test is z = -2.05. A) 0.0453 fail to reject the null hypothesis B) 0.0202; reject the null hypothesis C) 0.4798; fail to reject the null hypothesis D) 0.0404; reject the null hypothesis Assume that you plan to use a significance level of ? = 0.05 to test the claim that p1 = p2. Use the given sample sizes and numbers of successes to find the z test statistic for the hypothesis test. 50) A random sampling of sixty pitchers from the National League and fifty-two pitchers from the American League showed that 12 National and 7 American League pitchers had E.R.A.'s below 3.5. A) z = 0.919 B) z = 140.987 C) z = 1.195 D) z = 12.140
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Since we are testing the claim that $p_1 = p_2$, the null hypothesis is $H_0: p_1 - p_2 = 0$ and the alternative hypothesis is $H_a: p_1 - p_2 \neq 0$. Show more…
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Use the given information to find the P-value. Use the given significance level and state the conclusion about. A) P-value is 0.9744: fail to reject the null hypothesis. B) P-value is 0.0512: fail to reject the null hypothesis. C) P-value is 0.0512: reject the null hypothesis. D) P-value is 0.0256: reject the null hypothesis.
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