59) How many milliliters of a 1.125 M NaOH solution is required to neutralize a 25.00 mL sample of 0.5432 M nitric acid solution? HNO3 + NaOH Ă H2O + NaNO3
Added by Ian G.
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The balanced equation is: \[ \text{HNO}_3 + \text{NaOH} \rightarrow \text{H}_2\text{O} + \text{NaNO}_3 \] This shows that 1 mole of nitric acid reacts with 1 mole of sodium hydroxide. Show more…
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