Question

59% of all the towns residents own a dog and 69% own a cat. Of the dog owners 43% also own a cat. If a town resident is chosen at a random (round to 4 decimal places where possible) A. (Own a dog) = B. (Own a cat) = C. (Own a cat and a dog) = D (Own a dog GIVEN own a car)

          59% of all the towns residents own a dog and 69% own a cat. Of the dog owners 43% also own a cat. If a town resident is chosen at a random (round to 4 decimal places where possible)
A. (Own a dog) = 
B. (Own a cat) = 
C. (Own a cat and a dog) = 
D (Own a dog GIVEN own a car)

59% of all the towns residents own a dog and 69% own a cat. Of the dog owners 43% also own a cat. If a town resident is chosen at a random (round to 4 decimal places where possible)
A. (Own a dog) =
B. (Own a cat) =
C. (Own a cat and a dog) =
D (Own a dog GIVEN own a car)

Added by Jose E.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Sri K

10/08/2023

Step 1

59 P(Own a cat) = 0.69 P(Own a cat | Own a dog) = 0.43 We want to find P(Own a cat and a dog), which can be calculated using the conditional probability formula: P(Own a cat and a dog) = P(Own a cat | Own a dog) * P(Own a dog) Show more…

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59% of all the towns residents own a dog and 69% own a cat. Of the dog owners 43% also own a cat. If a town resident is chosen at a random (round to 4 decimal places where possible) A. (Own a dog) B . (Own a cat) C. (Own a cat and a dog )= D (Own a dog GIVEN own a car)