Question

A 59.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 175 mL of water. What is the final concentration? Assume the volumes are additive. concentration: M

          A 59.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 175 mL of water. What is the final concentration? Assume the volumes are additive.
concentration: M

A 59.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 175 mL of water. What is the final concentration? Assume the volumes are additive.
concentration: M

Added by Amanda S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

06/28/2022

Step 1

Given: \(M_1 = 0.20 \, \text{M}\) \(V_1 = 59 \, \text{mL}\) \(V_2 = 208 \, \text{mL}\) Plugging in the values: \(0.20 \, \text{M} \times 59 \, \text{mL} = M_2 \times 208 \, \text{mL}\) \(M_2 = \frac{0.20 \times 59}{208}\) \(M_2 = 0.0568 \, \text{M}\) Show more…

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A 59.0 mL aliquot of a 1.20 M solution is diluted to a total volume of 208 mL. A 104 mL portion of that solution is diluted by adding 175 mL of water. What is the final concentration? Assume the volumes are additive. concentration: