5. Consider ?ABCD (a) Why is ?ABCD not convex? (b) Which vertices lie in the interior of their corresponding opposite angles (i.e. Is A in interior of ?BCD , etc.) (c) Is m?ABC = m?ABD + m?DBC? (d) Is m?BAD = m?BAC + m?CAD?
Added by John T.
Close
Step 1
Step 1: ABCD is not convex because angle ADC is greater than 180 degrees. Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 72 other Geometry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In the figure below, $\mathrm{C}$ is the midpoint of $\overline{\mathrm{EA}}, \Varangle \mathrm{E}$ and $\Varangle \mathrm{A}$ are right angles, and $\mathrm{x} \mathrm{PCE}$ and $\Varangle \mathrm{ACN}$ are vertical angles. (FIGURE CANT COPY) Why is $\angle \mathrm{E}=\angle \mathrm{A} ?$
Congruent Triangles
Congruent Polygons
Let $A, B, C, D, E$ be the interior angles of a convex pentagon and $$ \Delta=\left|\begin{array}{lll} \cos A & \sin A & \sin (A+D+E) \\ \cos B & \sin B & \sin (B+D+E) \\ \cos C & \sin C & \sin (C+D+E) \end{array}\right| $$ then $\Delta(\pi 3)+\Delta^{\prime}\left(\pi^{\prime} 6\right)$ is
Explain why the Interior Angle Sum Theorem and the Exterior Angle Sum Theorem apply only to convex polygons.
Quadrilaterals
Angles of Polygons
Recommended Textbooks
Geometry A Common Core Curriculum
Geometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD