5A 1.5Ω 50 Ω 1:9 38 Ω 1:4 Circuito 3 V2 9Ω V3
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5Ω resistor. Since the current source is 5A, the current through the 1.5Ω resistor is also 5A. Therefore, the voltage across the 1.5Ω resistor is: $$V = IR = 5A \times 1.5\Omega = 7.5V$$ Show more…
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