00:01
And it having inductance l is equal to 60 mh we have to find its i instantaneous value of current.
00:09
For the purpose we can use the equation v is equal to i r plus l di by dt.
00:19
Now as di by dt we can find from the equation d by dt of v by r so which is equal to dv by dt.
00:35
In this case we have v is equal to 70 .7 sin 50 t we can write di by dt is equal to 50 into 70 .7 cos 50 t.
00:52
So now we can write equation in terms of i.
00:56
I is equal to v minus l di by dt whole divided by so we can write now i is equal to 70 .7 sin 50 t minus 60 into 10 raised to minus 3 into 50 into 70 .7 cos 50 t whole divided by 4.
01:35
This is the instantaneous value of current for our given system.
01:43
Now moving into the second part.
01:47
In the second part it is provided that we have a current through in rl circuit is 10 sin 377 t we have to find its voltage.
02:02
So v rms is equal to we can say 10 sin 377 t into plus 21 .22 into 10 raised to minus 3 into 3770 cos 50 t cos 377 t...