Question

5. For the water circulation system below, if the minimum power added to the water by the pump is defined as $hp[fi]=20-2000Q^2$ \rightarrow pump head, determine: a: the flow rate through the filter (Q in ft3/s), if the pump efficiency is 85%, and b: The pump work (HP). $K_{L ext} = 1.0$ $K_{L elbow} = 1.5$ $K_{L valve} =6.0$ $K_{L filter} = 12.0$ Filter Pump $K_{L ent}=0.8$ 200 ft. of 0.1-ft-diameter pipe with elD = 0.01

          5. For the water circulation system below, if the minimum power added to the water by the pump
is defined as $hp[fi]=20-2000Q^2$ \rightarrow pump head, determine: a: the flow rate through the
filter (Q in ft3/s), if the pump efficiency is 85%, and b: The pump work (HP).
$K_{L ext} = 1.0$
$K_{L elbow} = 1.5$
$K_{L valve} =6.0$
$K_{L filter} = 12.0$
Filter
Pump
$K_{L ent}=0.8$
200 ft. of 0.1-ft-diameter
pipe with elD = 0.01

5. For the water circulation system below, if the minimum power added to the water by the pump
is defined as hp[fi]=20-2000Q^2 →pump head, determine: a: the flow rate through the
filter (Q in ft3/s), if the pump efficiency is 85%, and b: The pump work (HP).
KL ext = 1.0
KL elbow = 1.5
KL valve =6.0
KL filter = 12.0
Filter
Pump
KL ent=0.8
200 ft. of 0.1-ft-diameter
pipe with elD = 0.01

Added by Karen K.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

Step 1

First, let's calculate the head loss in the pipe using the Darcy-Weisbach equation: hL = f * (L/D) * (V^2/2g) Where: hL = head loss (ft) f = friction factor L = length of the pipe (ft) D = diameter of the pipe (ft) V = velocity of the water (ft/s) g = Show more…

Show all steps

Thanks for your feedback!

For the water circulation system below, if the minimum power added to the water by the pump filter (Q in ft3/s), if the pump efficiency is 85%, and b: The pump work (HP). KLar = 1.0 kieben = 1.5 Kiwn = 6.0 K = 12.0 K = 0.8 200 ft. of 1.0-ft diameter pipe with eID = 0.01 Pump Filter