00:01
Dear students, we have to give ipc or systematic names for this following.
00:05
So let us start from the first one, numbering this in this way 1, 2, 3, 4, 5.
00:12
So 2 -bromo and 2 -methyl.
00:15
So the question here it is 2 -bromo, 2 -methyl, pentane.
00:29
Pentane, 5 carbon atoms that is why pentane.
00:32
Now this is, here we have 1 chlorine and 1 methyl substituent.
00:38
So we can write this position as 1.
00:40
We can write 1 -chloro, 1 -methyl, this is cyclohexane.
00:49
So cyclohexane.
00:54
Then coming to this one, here we have 2 chlorine atoms, here chlorine atom numbering from this 1, 2, 3.
01:01
So 1, 1 dichloro, 3 fluoro.
01:04
1, 1 dichloro, 3 fluoro, cycloheptane.
01:17
1, 2, 3, 4, cycloheptane.
01:20
Then coming to this one, here we have fluorine substituent.
01:25
The carbon it is treated as a substituent here and bromine substituent.
01:32
Now we have to select the longest chain here 1, 2, 3, 4, 5, 6.
01:38
We are going here up to here 6.
01:41
Here in this way if we move 1, 2, 3, 4, 5, 6.
01:45
1, 2, 3, 4, 5, 6, 7.
01:48
So this gives the longest chain 1, 2, 3, 4, 5, 6, 7.
01:54
Here bromine and fluorine both are treated as substituent...