00:01
Here, the circuit diagram of dc shund generator will be as follows.
00:15
So here, this is the diagram representing dc shunt generator.
00:20
Here this vl represents load voltage, il represents load current, i -s -h represents the shund current, v -s -h represents the potential difference across the shund.
00:31
Here ia represents r measure current and r sh represents the shund resistance so this is the diagram here the total load will be equal to we know that there are 500 lamps and each lamp has 100 watt so 500 into 100 this will be the total load and the unit of load is watt so this will be the total load present in the circuit now the current through the load will be equal to we know that power p equal to voltage into current or from here current i will be equal to power divided by voltage so using this relation we can find out the current through the load so here current through the load will be equal to power through the load divided by voltage across the load here power is equal to we know that there are 500 bulbs into 100 watt so this is the power across the load divided by the voltage across the road is given 250 volt upon solving this we will get the current across the load to be 200 and the unit of current is amberr.
01:36
Amber is the si unit of current.
01:39
Now we need to calculate the voltage drop in leads.
01:44
Here it is given, voltage drop in leads is given.
01:48
Let us represent this voltage to be vl.
01:52
Vl is equal to 10 volt.
01:54
Now the voltage across shunt field winding will be equal to so this potential difference or the voltage across the shund field winding is to be calculated represented by v of sh is equal to v plus vl.
02:14
V means 250 volt which is the voltage across the load plus this lead volt which is 10 volt so 250 plus 10 which is equal to 260 volt will be the voltage across the shund.
02:29
Now the current across the shend will be equal to i .sh is equal to we know that according to homslow i is equal to v by r that is voltage across the shend divided by the resistance across the shand.
02:40
Voltage across the shunt we have just now found out which is 260 volt divided by the resistance across the shand is already given the question which is 65 oom.
02:51
Upon solving this we will get the current across the shend to be 4 ampere.
02:56
Now the current across the armature is to be calculated.
03:00
Current across the armature, ia is equal to current across the load plus the current across the shend...