00:01
Hello student, in the given question we have to find out the probability that a student chosen at a random place neither soccer or noll nor volleyball.
00:14
So let event a, a be the event of playing soccer and b be the event of playing volleyball and ab is the group, ab is the event of playing both.
00:55
Now we have the given value as probability a is equal to 0 .41, probability of b is equal to 0 .30 and probability of a into b is equal to 0 .14.
01:12
Now we have the probability, the probability of playing, of playing at least one sport, at least one of the sport is calculate using the formula as probability of a or b is equal to probability of a plus probability of b minus probability of a into b.
02:00
So substituting above given value in this formula we get 0 .41 plus 0 .30 minus 0 .14 which is equal to 0 .57.
02:13
Therefore the probability of, therefore the probability of playing neither sport, playing neither sports is given by the formula the probability of neither a nor b which is equal to 1 minus probability of a or b.
02:55
So we have the value for probability of a or b as calculated here which is 0 .757.
03:06
So we get value for probability of neither a nor b is equal to 0 .43...