00:01
Hi there, so for this problem, we're told that an object is placed at a distance that is given.
00:05
That distance, it is 30 centimeters.
00:09
So then from a thin canvas lens along its access, the lens has a focal length that is given.
00:16
So the focal length for this is 15 centimeters.
00:22
Now, the object, so let's label that as you.
00:27
In this case, since we have a think of a lens, this will be at minus 30 centimeters, right? and what we need to determine is what are the values respectively of the image distance and the magnification.
00:48
So we need to obtain the image distance where we're going to label that as b and the magnification.
00:53
First, to determine the image distance, we can use.
00:58
The equation, the formula for lens, that will be that the inverse of the image distance equals to the inverse of the focal distance plus the inverse of the object distance.
01:18
So substituting the balance in here, this will be 1 divided by 15 minus 1 divided by 30.
01:25
We can put this in here as just 2 divided by 30...