Question

Calculate the force required to pull a stuffed toy duck (mass m = 1.70 kg) at a constant velocity of 3.8 m/s horizontally across the floor if the string is 44.0° above the horizontal. The coefficient of kinetic friction between the duck and the floor is 0.65. An elevator motor moves a car with six people upward at a constant speed of 2.90 m/s. The mass of the elevator is 6.60 × 10^2 kg, and the average mass of a person on the elevator is about 76.0 kg. Calculate the electric power that must be delivered to lift the elevator car, assuming half of the necessary power delivered goes into thermal energy.

          Calculate the force required to pull a stuffed toy duck (mass m = 1.70 kg) at a constant velocity of 3.8 m/s horizontally across the floor if the string is 44.0° above the horizontal. The coefficient of kinetic friction between the duck and the floor is 0.65.

An elevator motor moves a car with six people upward at a constant speed of 2.90 m/s. The mass of the elevator is 6.60 × 10^2 kg, and the average mass of a person on the elevator is about 76.0 kg. Calculate the electric power that must be delivered to lift the elevator car, assuming half of the necessary power delivered goes into thermal energy.

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University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Prachi Joshi

03/20/2022

Step 1

Given: - Mass of the duck, m = 1.70 kg - Velocity of the duck, v = 3.8 m/s - Angle above the horizontal, θ = 44° - Coefficient of kinetic friction, μ = 0.65 - Acceleration due to gravity, g = 10 m/s^2 The force required to move the duck upwards can be calculated Show more…

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Calculate the force required to pull a stuffed toy duck (mass m = 1.70 kg) at a constant velocity of 3.8 m/s horizontally across the floor if the string is 44.0° above the horizontal. The coefficient of kinetic friction between the duck and the floor is 0.65. An elevator motor moves a car with six people upward at a constant speed of 2.90 m/s. The mass of the elevator is 6.60 × 10^2 kg, and the average mass of a person on the elevator is about 76.0 kg. Calculate the electric power that must be delivered to lift the elevator car, assuming half of the necessary power delivered goes into thermal energy.

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Transcript

0:00 Hello everyone.

00:01 So here in this question it is given that there is a ramp which is elevated at 44 degrees.

00:11 This is sent upside and its weight is 1 .5 g g.

00:16 This is a duck.

00:18 Initially it had velocity that is a constant velocity at 3 .8 meter per second.

00:25 It is given to us.

00:26 And if it is given that there is a constant velocity, that means there is zero acceleration.

00:31 There is no acceleration.

00:33 Applied here.

00:35 Here it is not a smooth surface, it is a rough surface so frictional coefficient is 0 .65.

00:44 We have to calculate the force to move this above the plane.

00:49 So here if we have to apply this force without any acceleration, so here will be mg sine theta that will be applied.

00:58 And here frictional force will be applied because the movement of this object is upward.

01:05 So frictional force will be downward.

01:07 So we can say that force that should be applied to move it upwards should be mg sine theta plus frictional force.

01:16 So mass is given as 1 .5.

01:18 G we can take as 10 meter per second square, sine theta, sine 44 degrees.

01:24 Plus frictional force will be mu mg cos theta because normal reaction will be equal to mg cos theta...

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