6. Calculate the maximum solubility in terms of mole fraction of solid naphthalene in liquid toluene at 25 oC is the enthalpy of fusion of naphthalene is 19.123 kJ/mol and its melting point is 78.2 oC.
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Given: T = 25°C Convert to Kelvin: T = 25°C + 273 = 298 K Show more…
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Madhur L.
Calculate the solubility of naphthalene at 25.0 °C in any solvent in which it forms an ideal solution. The melting point of naphthalene is 80.0 °C, and the enthalpy of fusion is 19.19 kJ/mol. (Hint: solubility can be expressed as mole fraction)
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The molar heat of fusion of benzene $\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ is 9.92 $\mathrm{kJ} / \mathrm{mol}$ . Its molar heat of vaporization is 30.7 $\mathrm{kJ} / \mathrm{mol}$ . Calculate the heat required to melt 8.25 $\mathrm{g}$ benzene at its normal melting point. Calculate the heat required to vaporize 8.25 g benzene at its normal boiling point. Why is the heat of vaporization more than three times the heat of fusion?
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