Question

6. Draw a molecular orbital diagram for each of the following combinations of orbitals. Make sure the starting relative energies of the orbitals are correct, and draw the shape of both the bonding and antibonding orbitals formed. C sp3 with O sp3 C p orbital with N p orbital O sp3 with H C sp3 with C sp

          6. Draw a molecular orbital diagram for each of the following combinations of orbitals. Make sure the starting relative energies of the orbitals are correct, and draw the shape of both the bonding and antibonding orbitals formed.

C sp3 with O sp3

C p orbital with N p orbital

O sp3 with H

C sp3 with C sp

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6. Draw a molecular orbital diagram for each of the following combinations of orbitals. Make sure the starting relative energies of the orbitals are correct, and draw the shape of both the bonding and antibonding orbitals formed.

C sp3 with O sp3

C p orbital with N p orbital

O sp3 with H

C sp3 with C sp

Added by Collin H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/28/2022

Step 1

C sp3 with O sp3: Carbon and oxygen both have sp3 hybrid orbitals. When these orbitals overlap, they form a sigma bond (σ) and a sigma antibond (σ*). The sigma bond is lower in energy and more stable, while the sigma antibond is higher in energy and less stable. Show more…

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6. Draw molecular orbital diagrams for each of the following combinations of orbitals. Make sure the starting relative energies of the orbitals are correct, and draw the shape of both the bonding and antibonding orbitals formed. C sp3 with O sp3 C p orbital with N p orbital O sp3 with H C sp3 with C sp

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Transcript

00:01 In this question we are assembled at the task to draw the molecular orbitals of for the given combinations and we got to draw both the bonding and anti -bonding orbitals.

00:15 First combination given is combination of sp3 -hybterized orbital of carbon with sp3 hybridized orbital of oxygen.

00:24 First let us give the shape of sp3 -3 hypatized orbital, one of the sp3 hybridized orbital.

00:30 Like this we'll have sp3 orbitals that is 4 sp3 orbitals directed towards each corner of a tetrahedron and the sp3 orbital of oxygen is represented in green color energy of oxygen sp3 will be lower than the energy of carbon's sp3 orbital because the electronegativity of oxygen is higher compared to carbon the species with higher electronegativity will have lower energy this is the bonding orbital.

01:09 The two larger lobes of the sp3 -habitable orbitals will combine together to form the bonding orbital.

01:15 That is the shape of an anti -bonding orbital.

01:18 One of the lower lobe, that is small lobe, will combine with a larger lobe of another orbital.

01:24 And there is a node.

01:26 Now it is more to the second combination.

01:28 It is the combination of b orbital of carbon with b orbital of nitrogen.

01:33 Let us take this as p -z orbital.

01:37 Nitrogen's pez will have lower energy compared to the carbon's phs it as nitrogen is relatively electronegative than carbon.

01:47 The bonding between the pez orbitals of carbon and nitrogen will be lateral overlap.

01:54 So the resulting bond will be a bi -bon.

01:58 This is the shape of bonding orbital and an anti -bonding orbital will look like...

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