Question

6) Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H0 for the level of significance ?. Two-tailed test z = 1.95 ? = 0.05 A) 0.0512; fail to reject H0 B) 0.0512; reject H0 C) 0.0256; reject H0 D) 0.9744; fail to reject H0

          6) Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H0 for the level of significance ?.

Two-tailed test
z = 1.95
? = 0.05
A) 0.0512; fail to reject H0
B) 0.0512; reject H0
C) 0.0256; reject H0
D) 0.9744; fail to reject H0

6) Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H0 for the level of significance ?.

Two-tailed test
z = 1.95
? = 0.05
A) 0.0512; fail to reject H0
B) 0.0512; reject H0
C) 0.0256; reject H0
D) 0.9744; fail to reject H0

Added by Felix S.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Qudsiya Anis

06/06/2022

Step 1

Given that the standardized test statistic z = 1.95, for a two-tailed test, the p-value is equal to twice the probability of z being greater than 1.95. From the standard normal distribution table, the probability of z being greater than 1.95 is 0.0256. Therefore, Show more…

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6) Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H0 for the level of significance ̑. Two-tailed test z = 1.95 ̑ = 0.05 A) 0.0512; fail to reject H0 B) 0.0512; reject H0 C) 0.0256; reject H0 D) 0.9744; fail to reject H0