00:01
In this question we have the value of power p which is equal to 2 .5 kilowatt.
00:06
So it becomes 2 5 .0 watt and v voltage which is equal to 250 voltage.
00:15
So here we can first write down the expiration of power p which is equals to v squared divided by r equivalent.
00:23
So it becomes r equivalent which is equals to v squared divided by p.
00:30
We can write it as 250 square divided by this 2500.
00:36
So on a simplified condition, it becomes 25 oom.
00:40
Then we can write this r equivalent, which is equals to r1 multiplied by r2 divided by r1 plus r2 plus r3 multiplied by rx divided by r3 plus r3 plus rx.
00:58
Now we have all the values here, that is this r equivalent which is equal to 25 om, then r1 which is equals to 15 ome, r2 which is equals to 10 oom, r3 which is equals to 38 om, and rx that we want to find out.
01:19
Okay, so from this we can write down all the or substitute all the values here.
01:27
So it becomes a which is equal to 15, 15 multiplied by 10 divided by 15 plus 10 plus 38 multiplied by rx divided by 38 plus rx.
01:42
So now let's simplify it and we get the value of rx which is equal to 38 oom.
01:50
So this is the answer of a first part that is the value of a resistance at the x...