R?=4? R?=8? R?=5? R?=1? V=60V R?=6? R?=3?
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We have R = 4Ω, R' = S, R = 5Ω, R = 19Ω, and R = 6Ω. Show more…
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The circuit shown in fig consists of the following $\mathrm{E}_{1}=6, \mathrm{E}_{2}=2, \mathrm{E}_{3}=3$ volt $\mathrm{R}_{1}=6, \mathrm{R}_{4}=3 \mathrm{Ohm}$ $\mathrm{R}_{3}=4, \mathrm{R}_{2}=2 \mathrm{Ohm}$ $\mathrm{C}=5 \mu \mathrm{F}$$E_{1}=6 \mathrm{~V} \quad E_{2}=2 \mathrm{~V} \quad E_{3}=3 \mathrm{~V} \quad \mathrm{R}_{1}=6 \Omega$ $\mathrm{R}_{2}=2 \Omega \quad \mathrm{R}_{3}=4 \Omega \quad \mathrm{R}_{4}=3 \Omega$ The current in resistance $\mathrm{R}_{1}$ is. (A) $0.5 \mathrm{~A}$ (B) $1.0 \mathrm{~A}$ (C) $1.5 \mathrm{~A}$ (D) Zero
The circuit shown in fig consists of the following $E_{1}=6, E_{2}=2, E_{3}=3$ Volt $\mathrm{R}_{1}=6, \mathrm{R}_{4}=3 \mathrm{Ohm}$ $\mathrm{R}_{3}=4, \mathrm{R}_{2}=2$ Ohm $\mathrm{C}=5 \mu \mathrm{F}$$E_{1}=6 \mathrm{~V} \quad E_{2}=2 \mathrm{~V} \quad E_{3}=3 \mathrm{~V} \quad \mathrm{R}_{1}=6 \Omega$ $\mathrm{R}_{2}=2 \Omega \quad \mathrm{R}_{3}=4 \Omega \quad \mathrm{R}_{4}=3 \Omega$ The current through resistance $\mathrm{R}_{3}$ is. (A) $1.5 \mathrm{~A}$ (B) $1.2 \mathrm{~A}$ (C) $0.9 \mathrm{~A}$ (D) $0.6 \mathrm{~A}$
The total resistance of a circuit is given by the formula RT = R1 + R2. R1 = 4 + 6i ohms and R2 = 2 - 4i ohms. What is RT?
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