Question

Qn. 6 In an experiment, a solution containing 0.0837 M Na+ and 0.0666 M K+ gave chromatographic peaks of 423 and 347 (arbitrary units) respectively. To analyze the unknown, 5.0 mL of 0.146 M K+ were added to 10.0 mL of unknown, and diluted to 50.0 mL with a volumetric flask. The peaks measured 553 and 582 units respectively. a) Calculate the response factor for the analyte. b) Find the concentration of the K+ in the 50.0 mL mixture. c) Find the concentration of the Na+ in the 50.0mL mixture? d) Find the concentration of Na+ in the original unknown sample.

          Qn. 6 In an experiment, a solution containing 0.0837 M Na+ and 0.0666 M K+ gave chromatographic peaks of 423 and 347 (arbitrary units) respectively. To analyze the unknown, 5.0 mL of 0.146 M K+ were added to 10.0 mL of unknown, and diluted to 50.0 mL with a volumetric flask. The peaks measured 553 and 582 units respectively.
a) Calculate the response factor for the analyte.
b) Find the concentration of the K+ in the 50.0 mL mixture.
c) Find the concentration of the Na+ in the 50.0mL mixture?
d) Find the concentration of Na+ in the original unknown sample.

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Qn. 6 In an experiment, a solution containing 0.0837 M Na+ and 0.0666 M K+ gave chromatographic peaks of 423 and 347 (arbitrary units) respectively. To analyze the unknown, 5.0 mL of 0.146 M K+ were added to 10.0 mL of unknown, and diluted to 50.0 mL with a volumetric flask. The peaks measured 553 and 582 units respectively.
a) Calculate the response factor for the analyte.
b) Find the concentration of the K+ in the 50.0 mL mixture.
c) Find the concentration of the Na+ in the 50.0mL mixture?
d) Find the concentration of Na+ in the original unknown sample.

Added by Kari P.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/16/2023

Step 1

The response factor (RF) is the ratio of the chromatographic peak to the concentration of the ion. We can calculate the response factors for Na+ and K+ using the given data: RF(Na+) = Peak(Na+) / Concentration(Na+) RF(Na+) = 423 / 0.0837 RF(K+) = Peak(K+) / Show more…

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In an experiment, a solution containing 0.0837 M Na+ and 0.0666 M K+ gave chromatographic peaks of 423 and 347 (arbitrary units) respectively. To analyze the unknown, 5.0 mL of 0.146 M K+ were added to 10.0 mL of the unknown and diluted to 50.0 mL with a volumetric flask. The peaks measured 553 and 582 units respectively. a) Calculate the response factor for the analyte. b) Find the concentration of the K+ in the 50.0 mL mixture. c) Find the concentration of the Na+ in the 50.0 mL mixture. d) Find the concentration of Na+ in the original unknown sample.

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