(6) In the circuit shown below, use the source transformation method to find $I_o$. $i_a$ $I_o$ 2 $\Omega$ 4 $\Omega$ 12 $\Omega$ + 12 V 12 $\Omega$ 3 A 6A + 12 V --- OCR End ---
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The current source value is $12V / 12\Omega = 1A$. Show more…
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