Question

6. Inverse Dynamics: The diagram below opposite is of one forearm/hand segment holding a load, and an upper arm segment. The situation is static. The diagram does not include all forces and moments. Given the information in the diagram (assume anthropometry of 50\% male), calculate the shoulder muscle moment $M_2$ using inverse dynamics. By this I mean you should show the equations where you have calculated the net force and moment at the distal end of the humerus, and calculated $M_2$ via one last equation that is just focused on the upper arm segment. [6] $M_2 = ?$ $-60^\circ$ $R_{y1} = 200\text{ N}$ $M_1 = 66.2$ $-11.8$ $-188.2\text{ N}$ load and hand

          6. Inverse Dynamics: The diagram below opposite is of one forearm/hand segment holding
a load, and an upper arm segment. The situation is static. The diagram does not include
all forces and moments.
Given the information in the diagram
(assume anthropometry of 50\% male),
calculate the shoulder muscle
moment $M_2$ using inverse dynamics.
By this I mean you should show the
equations where you have calculated
the net force and moment at the distal
end of the humerus, and calculated $M_2$
via one last equation that is just
focused on the upper arm segment.
[6]
$M_2 = ?$
$-60^\circ$
$R_{y1} = 200\text{ N}$
$M_1 = 66.2$
$-11.8$
$-188.2\text{ N}$ 
load and hand

6. Inverse Dynamics: The diagram below opposite is of one forearm/hand segment holding
a load, and an upper arm segment. The situation is static. The diagram does not include
all forces and moments.
Given the information in the diagram
(assume anthropometry of 50% male),
calculate the shoulder muscle
moment M2 using inverse dynamics.
By this I mean you should show the
equations where you have calculated
the net force and moment at the distal
end of the humerus, and calculated M2
via one last equation that is just
focused on the upper arm segment.
[6]
M2 = ?
-60^∘
Ry1 = 200 N
M1 = 66.2
-11.8
-188.2 N
load and hand

Added by Brandon S.

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