00:09
For chapter 4, section 6, question 59a, we're to write a linear function.
00:18
So we have y equals, and m is going to be a rate of change.
00:22
So we have a decrease in value of the car at $2 ,920 plus that's times t, plus its initial value, which is $29 ,200.
00:40
For b, we know that y is going to equal the initial value times the rate of change per year, which we're given as 80%.
00:51
We can write as a decimal time to the power of t.
01:03
Then for c, we're going to determine f of 5 and f of 10 using our linear model.
01:21
So in my calculator, i'm going to type in negative 2 ,920 times 5 plus 29 ,200, which gives the value of the vehicle at $14 ,600.
01:41
And then i'm going to change that 5 here to 10...