Question

6. Multiply : (i) \( \frac{3}{20} \) by \( \frac{15}{18} \) (ii) \( \frac{-5}{36} \) by \( \frac{-3}{20}= \) (iii) \( \frac{36}{7} \) by \( \frac{-14}{9} \) (iv) \( \frac{-36}{5} \) by \( \frac{25}{-9} \) (v) \( \frac{14}{9} \) by \( \frac{-8}{3} \) (vi) \( \frac{15}{4} \) by \( \frac{-4}{7} \) 7. Simplify :

          6. Multiply :
(i) \( \frac{3}{20} \) by \( \frac{15}{18} \)
(ii) \( \frac{-5}{36} \) by \( \frac{-3}{20}= \)
(iii) \( \frac{36}{7} \) by \( \frac{-14}{9} \)
(iv) \( \frac{-36}{5} \) by \( \frac{25}{-9} \)
(v) \( \frac{14}{9} \) by \( \frac{-8}{3} \)
(vi) \( \frac{15}{4} \) by \( \frac{-4}{7} \)
7. Simplify :

6. Multiply :
(i) (3)/(20) by (15)/(18)
(ii) (-5)/(36) by (-3)/(20)=
(iii) (36)/(7) by (-14)/(9)
(iv) (-36)/(5) by (25)/(-9)
(v) (14)/(9) by (-8)/(3)
(vi) (15)/(4) by (-4)/(7)
7. Simplify :

Added by Seth W.

Algebra for College Students

Mark Dugopolski 5th Edition

Chapter 6

Instant Answer

Solved by Expert Amy Jiang

04/20/2020

Step 1

(i) \( \frac{3}{20} \) by \( \frac{15}{18} \) \[ \frac{3 \times 15}{20 \times 18} = \frac{45}{360} \] (ii) \( \frac{-5}{36} \) by \( \frac{-3}{20} \) \[ \frac{-5 \times -3}{36 \times 20} = \frac{15}{720} \] (iii) \( \frac{36}{7} \) by \( \frac{-14}{9} Show more…

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6. Multiply : (i) \( \frac{3}{20} \) by \( \frac{15}{18} \) (ii) \( \frac{-5}{36} \) by \( \frac{-3}{20}= \) (iii) \( \frac{36}{7} \) by \( \frac{-14}{9} \) (iv) \( \frac{-36}{5} \) by \( \frac{25}{-9} \) (v) \( \frac{14}{9} \) by \( \frac{-8}{3} \) (vi) \( \frac{15}{4} \) by \( \frac{-4}{7} \) 7. Simplify :