Question

22. (6 pts.) Determine the position of the equilibrium for each of the following reaction based on the $pK_a$ values: HC$\equiv$CH a. $pK_a = 25$ $K_{eq}$ $\qquad \longrightarrow$ HC$\equiv$C$^-$ + NH$_2$ $pK_a = 38$ HC$\equiv$CH b. $pK_a = 25$ $K_{eq}$ $\qquad \longrightarrow$ HC$\equiv$C$^-$ + OH$^-$ $pK_a = 16

          22. (6 pts.) Determine the position of the equilibrium for each of the following reaction based
on the $pK_a$ values:
HC$\equiv$CH
a.
$pK_a = 25$
$K_{eq}$
$\qquad \longrightarrow$
HC$\equiv$C$^-$ + NH$_2$
$pK_a = 38$
HC$\equiv$CH
b.
$pK_a = 25$
$K_{eq}$
$\qquad \longrightarrow$
HC$\equiv$C$^-$ + OH$^-$
$pK_a = 16

22. (6 pts.) Determine the position of the equilibrium for each of the following reaction based
on the pKa values:
HC≡CH
a.
pKa = 25
Keq
⟶
HC≡C^- + NH2
pKa = 38
HC≡CH
b.
pKa = 25
Keq
⟶
HC≡C^- + OH^-
pKa = 16

Added by Leslie V.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Shaiju T

04/28/2022

Step 1

For reaction a: pKa of HC≡CH = 25 pKa of HCCH = 22 Since the pKa of HC≡CH is higher than the pKa of HCCH, the equilibrium will favor the formation of HCCH. For reaction b: pKa of HC≡CH = 16 pKa of HCCH = 38 Since the pKa of HC≡CH is lower than the pKa of HCCH, Show more…

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(6 pts.) Determine the position of the equilibrium for each of the following reaction based on the pKa values: a. b. b. pK=25 HC==CH pK=25 HCCH on the pKa values: Keg 22. (6 pts.) Determine the position of the equilibrium for each of the following reaction based pK=16 pK=38