00:01
So here in this question we are given an elbow, let's say this is the elbow.
00:06
Here, the volume here in this part is v1 and which is here the volume, this is v2.
00:13
The pressure in this first part, or we can say that first, this is p1 and area is a1.
00:20
Here the pressure is p2 and area is a2.
00:24
And this distance is 40 centimeters.
00:31
This is making an angle of 45 degree with the horizontal so from here we are given the water mass flow rate that is equals to 30 kilogram per second we are given the area of section 1 that is a 1 which will be equals to 150 centimeter square that will be equals to 0 .015 square we are given the area of section 2 that is a 2 that will be equals to 25 centimeter square that will comes out to be 0 .0025 meter square so from here mass of the water elbow, m -not will comes out to be 50 kilogram and the momentum flux factor that is beta will come out to be 1 .03.
01:11
So from here we can say that m -0 will be rho a1 v1 that will be equals to r -a2 v2.
01:18
So from here m -not is 30 that will be equals to density of water is thousand multiplied by the area that is 0 .015 multiplied by the v1 that will be equals to thousand multiplied by the 0 .0025 multiplied by the a2.
01:34
So individually equating all this term.
01:38
So from the first part we get the value of v1 as 2 meter per second and we get the value of v2 as 12 meter per second.
01:46
So here we are applying the bernoulli's theorem on section 1 and 2.
01:53
So according to the bernoulli's theorem, p1 divided by the row g plus v1 raised to the power 2 divided by the 2g will be equals to p2 divided by the row g plus v2 raised to the power 2 divided by the 2g plus z 2 so from here p 2 is equal to p a so from here we can say that p a divided by the row multiply by the g will be equals to 10 .3 meter so from here we get the value of p a which comes out to be 11043 pascal so from here we can say that p1 divided by the thousand multiply by the 9 .8 plus 4 divided beta to multiply by the 9 .8, that will be close to 10 .3 plus 144 divided by the 2 multiply by the 9 .8 plus 0 .40.
02:40
So from here, after simplifying this term, we get the value of p1 as 174971 .16 pascal.
02:47
And from here, this is the value of p1.
02:50
So from here we can say that vix is 2 meter per second.
02:54
V1 .y is 0...