00:01
Let's discuss this question.
00:01
So here we have a diagram where a steel wire is used to stretch a spring by the hanging a mass over a frictionless, massless fixed pulley.
00:10
So we need to find the frequency of the wire and also we need to find if the mass is now put into oscillations with the amplitude of 0 .15 meters.
00:22
So what are the wires frequencies at the uppermost and lowermost points.
00:27
So v is equal to under root.
00:34
K x divided by m divided by l.
00:38
So v will be equal to under root xl divided by m.
00:44
Here we can say wavelength is equal to lambda and frequency is equal to f that is equal to b divided by lambda which is equal to 1 divided by lambda multiplied by under root k xl divided by m so here we have a where lambda is equal to to 1 meter, mass is equal to 30, 45 by 10 raise to minus 3 kilograms, k is equal to 179 newton per meter, x is equal to 0 .514 meter and here l is equal to 2 meter and we all know that frequency is equal 1 divided by 1 multiplied by and here frequency that is f is equal to 1 divided by 1 multiplied by under root 179 multiplied by 0 .154.
01:57
Frequency is equal to 1 divided by 1, under root 179 multiplied by 0 .514 multiplied by 2 divided by 35 multiplied by 10 raise to minus 3.
02:10
So here frequency f is equal to 75 hertz.
02:18
Now here we can say solving for b...