6 the permanganate ion mno4 reacts in a basic medium with...

Name: 6 the permanganate ion mno4 reacts in a basic medium with the iodide ion 1 to give molecular iodine 12 and manganese oxide mno2 identifies the redox couples involved gives the oxidation reac 62898
Uploaded: 2022-04-11T20:10:52-08:00
Duration: 7 min 7 s
Channel: Sri K
Description: 6 the permanganate ion mno4 reacts in a basic medium with the iodide ion 1 to give molecular iodine 12 and manganese oxide mno2 identifies the redox couples involved gives the oxidation reac 62898

6. The permanganate ion (MnO4) reacts in a basic medium with the iodide ion (1) to give molecular iodine (12) and manganese oxide (MnO2) identifies the redox couples involved - Gives the oxidation reaction takes place - Give the reduction reaction takes place - Give the balanced equation of the reaction

Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium iodide: MnO4-(aq) + I-(aq) → MnO2(s) + I2(aq) + H2O(l) + OH-(aq) Since this reaction takes place in basic solution, H2O(l) and OH-(aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: MnO4-(aq) + I-(aq) + H2O(l) + OH-(aq) → MnO2(s) + I2(aq) + H2O(l) + OH-(aq) Part B What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(l) and OH-(aq) in the blanks where appropriate. Your answer should have six terms. Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3). Include coefficients of 1, as required, for grading purposes.

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