00:01
In this first problem, you're being asked to solve the given trick equations and turns of degrees.
00:04
Well, the first thing i'm going to do is set it equal to zero by subtracting the sine of theta from both sides of our equation.
00:11
So that means we'll be left with the sign of theta times the tangent of theta minus the sign of theta equals zero.
00:19
Well, now we can factor our sign of theta out like a jada's common factor.
00:23
So if the sign of theta, and when we divide both turns by the sine of theta, that will leave us with the tangent of theta.
00:30
Theta minus 1.
00:32
Well, now that our equation is solved, it's factor, now we can go ahead and set each factor equal to 0.
00:38
So we'll have the sine of theta equal to 0, and the tangent of theta minus 1 could equal to 0.
00:45
Well, sign is 0.
00:46
Well, remember, sine is our y coordinate, so this happens at both 0 and 180 degrees.
00:52
So that would be two of our answers.
00:54
Now, to solve the second equation, we'll add one to both sides.
00:57
So we'll have the tangent of theta is equal to 1.
01:00
Well, tangent of theta is equal to 1.
01:03
That happens at 45 degrees.
01:05
But remember, tangent is also positive in the third quadrant.
01:09
So in the third quadrant, if our reference angle is 45, that means we would have a 225, oops, that's way too many twos.
01:15
We would have a 225 degree angle.
01:18
So perfect.
01:19
Now we have all four of our answers.
01:21
It be 0, 45, 180, and 225.
01:24
So if you're looking at at your answer choices as that first one, which i'll call a.
01:29
Okay, so now let's scroll down and let's take a look at your second problem.
01:33
So you were given this triangle, and i'm going to try and draw it in here, as best as i can...