2. A 6.00 cm tall object is placed 12.0 cm from a lens that has a focal length of 26.0 cm. a. What is the image distance? b. Is the image real or virtual? c. What is the magnification? d. Is the image upright or inverted? e. What is the image height?
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Given: f = 26.0 cm u = -12.0 cm (negative because the object is placed on the opposite side of the lens) Plugging in the values: 1/26.0 = 1/v - 1/-12.0 Simplifying: 1/26.0 = 1/v + 1/12.0 To solve for v, we can take the reciprocal of both sides: 26.0 = v + Show more…
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