Question

622 CHAPTER 24 24.16 What is the resistance of a 2-m-long aluminum wire having a diameter of 10 mm. The resistivity of aluminum is $2.826 \times 10^{-8} \Omega \cdot m$.

Name: 622 chapter 24 2416 what is the resistance of a 2 m long aluminum wire having a diameter of 10 mm the resistivity of aluminum is 2826 times 10 8 omega cdot m 06899
Uploaded: 2023-06-21T11:50:46-08:00
Duration: 1 min 53 s
Channel: Adi S
Description: 622 chapter 24 2416 what is the resistance of a 2 m long aluminum wire having a diameter of 10 mm the resistivity of aluminum is 2826 times 10 8 omega cdot m 06899

          622 CHAPTER 24
24.16 What is the resistance of a 2-m-long aluminum wire having a diameter of 10 mm. The resistivity of aluminum is $2.826 \times 10^{-8} \Omega \cdot m$.

622 chapter 24 2416 what is the resistance of a 2 m long aluminum wire having a diameter of 10 mm the resistivity of aluminum is 2826 times 10 8 omega cdot m 06899

Added by Stefanie S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Adi S

06/21/2023

Step 1

The formula for resistance (R) is: $R = \rho \frac{L}{A}$ where: $\rho$ is the resistivity of the material L is the length of the wire A is the cross-sectional area of the wire Given values: Length of the wire, L = 2 m Diameter of the wire, d = 10 mm Resistivity Show more…

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622 CHAPTER 24 24.16 What is the resistance of a 2-m-long aluminum wire having a diameter of 10 mm. The resistivity of aluminum is $2.826 \times 10^{-8} \Omega \cdot m$.