- Molar mass of glucose \( \left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right) \) is \( 6(12.01) + 12(1.01) + 6(16.00) = 180.18 \, \text{g/mol} \).
- Moles of glucose = \(\frac{28.4 \, \text{g}}{180.18 \, \text{g/mol}} = 0.1576 \, \text{mol}\).
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