A 0.9157-g mixture of CaBr2 and NaBr is dissolved in water, and AgNO3 is added to the solution to form AgBr precipitate. If the mass of the precipitate is 1.7040 g, what is the percent by mass of NaBr in the original mixture?
Added by Harneet K.
Step 1
First, we need to find the moles of AgBr formed. To do this, we can use the molar mass of AgBr, which is 187.77 g/mol. moles of AgBr = mass of AgBr / molar mass of AgBr moles of AgBr = 1.7040 g / 187.77 g/mol = 0.00907 mol Show more…
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