69. There is a current of 0.25 A in the circuit of Figure...

69. There is a current of 0.25 A in the circuit of Figure P23.69. INT a. What is the direction of the current? Explain. b. What is the value of the resistance R? c. What is the power dissipated by R? d. Make a graph of potential versus position, starting from V = 0 V in the lower left corner and proceeding clockwise. See Figure P23.9 for an example.

Transcript

00:01 In this question, this is a circuit where 6 volt of battery is connected and 12 volt of battery is also connected.

00:11 12 volt of battery will try to dissipate current in counterclockwise direction and 6 bolt of battery will try to dissipate current in clockwise direction.

00:23 But 12 volt will be more dominant and the net flow of current will be in counterclockwise.

00:31 Direction.

00:32 Question we have been also provided by the amount of current that is flowing through the circuit which is 0 .25 ampere.

00:40 We have to find this unknown resistance are for that we will use kirchop's law.

00:46 We can write sigma del v i is equal to 12 volt minus i multiplied by 12 volt minus i multiplied by 6 om sorry this will be ome minus 6 volt minus i r which is equal to 0 when we will solve this by putting value of i is equal to 0 .25 we will get r is equal to 6 om so the value of unknown resistance is 6 om we also need to find the power dissipated by this resistance r, we will write the formula i squared multiplied by r.

01:33 So this will be 0 .25 squared multiplied by 6.

01:38 So the power dissipated will be 0 .38 watts.

01:44 This will be our answer for power dissipated.

01:48 We will write the direction of current will be counterclockwise.

01:56 Because 12 volt battery will dominate its current trend over 6 volt battery.

02:10 Now moving towards the last question, we have to take lower left corner as 0 volt and we have to plot a graph with distance in clockwise direction as the clockwise direction is opposite to the direction of current...

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