6. A block of concrete weighs 100-lb in air (density of air = 1.23-kg/mĀ³) and weighs only 60-lb when immersed in water. What is the specific weight of the block? ? = W/V ? = 444.8 N / 36.863 W = mg 100 lb (4.448 N / 1 lb) = m (9.81 m/sĀ²) m = 45.3 kg V = m/? V = 45.3 kg / 1.23 kg/mĀ³ ?w = W/V 9810 N/mĀ³ = (60 lb)(4.448 N/lb) / V V = 0.027 mĀ³
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The buoyant force is the difference between the weight of the block in air and the weight of the block in water. \[ F_b = W_{\text{air}} - W_{\text{water}} \] \[ F_b = 100 \, \text{lb} - 60 \, \text{lb} = 40 \, \text{lb} \] Show moreā¦
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