Question

6. EFTS, Lorentz model of an insulator. Derive the terms for dispersion and absorption parts of the dielectric response, by taking the real part of the time-dependent position, $\mathcal{R}\{x(t)\}$, of the electronic charge e, under the influence of an external electric field $E_z = E_0 e^{i\omega t}$, i.e. solve $\ddot{x} + 2\gamma \dot{x} + \omega_0^2 x = -\frac{eE_0}{m_e} e^{i\omega t}$

          6. EFTS, Lorentz model of an insulator.
Derive the terms for dispersion and absorption parts of the dielectric response, by
taking the real part of the time-dependent position, \(\mathcal{R}\{x(t)\}\), of the electronic charge
e, under the influence of an external electric field \(E_z = E_0 e^{i\omega t}\), i.e. solve
\(\ddot{x} + 2\gamma \dot{x} + \omega_0^2 x = -\frac{eE_0}{m_e} e^{i\omega t}\)

$6. EFTS, Lorentz model of an insulator. Derive the terms for dispersion and absorption parts of the dielectric response, by taking the real part of the time-dependent position, ℛ{x(t)}, of the electronic charge e, under the influence of an external electric field Ez = E0 e^iω t, i.e. solve ẍ + 2γẋ + ω0^2 x = -(eE0)/(me) e^iω t$

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