7. 1.00 mol \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \) (glucose) is oxidized to carbon dioxide and water at \( 25^{\circ} \mathrm{C} \) according to the following equation; \[ \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s})+6 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \] Calorimetric measurements give \( \Delta_{r} U^{\circ}=-2808 \mathrm{~kJ} \mathrm{~mol}^{-1} \) and \( \Delta_{\mathrm{r}} \mathrm{S}^{\circ}=+259.1 \mathrm{JK}^{-1} \mathrm{~mol}^{-1} \) at \( 25^{\circ} \mathrm{C} \). How much of this energy can be extracted as (a) heat (at constant pressure), (b) work?
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- \( \Delta_{r} U^{\circ} = -2808 \, \text{kJ mol}^{-1} \) - \( \Delta_{r} S^{\circ} = +259.1 \, \text{J K}^{-1} \text{mol}^{-1} \) - Temperature \( T = 25^{\circ} \text{C} = 298 \, \text{K} \) Show more…
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When 1.000 mol C6H12O6 (glucose) is oxidized to carbon dioxide and water at 25°C according to the equation C6H12O6(s) + 6 O2(g) → 6 CO2(g) + 6 H2O(l), calorimetric measurements give ΔrU = -2808 kJ mol^(-1) and ΔrS = +182.4 J K^(-1) mol^(-1) at 25°C. How much of this energy change can be extracted as (a) heat at constant pressure (ΔrH), (b) work (ΔrA)?
Sri K.
Text: Combustion of compounds called sugars produces CO2 and H2O. The reaction for glucose is shown below. A sample of glucose with a mass of 1.46 g was burned in a calorimeter, and 24.00 kJ of heat was liberated. Determine the heat of reaction for glucose by answering the following questions: (a) Assuming the sugar is pure glucose, C6H12O6, give the balanced reaction for this reaction. C6H12O6(s) + 6O2 (g) -> 6CO2 (g) + 6H2O (l) (b) Calculate the moles of sugar present in the sample described above. __________ moles C6H12O6 (c) Calculate the heat for this reaction if 1.00 mole of sugar is used. Hint: Use a factor of moles/kJ from (a) using the fact that 24.00 kJ was released (exothermic!) for 1.46 g glucose. DH = ___________ kJ/mol
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