00:01
We're going to start this problem by creating a probability tree, showing the probabilities of defects and not defects among the supplies delivered by the three suppliers.
00:13
So a company manufacturing electronic components for home entertainment systems buys electrical contractors from c3 suppliers, supplier a, supplier b, and supplier c.
00:30
Supplier a can only deliver 65 % of the components needed.
00:38
Whereas the company must also purchase connectors from the two other suppliers, 20 % comes from supplier b and the rest come from supplier c.
00:50
So the 65 and the 20 add up to 85%.
00:54
So that means there's 15 % that has to come from supplier c.
00:58
Now, this company liked supplier a because when a delivers, they only deliver with a defective rate of 0 .01 or 1%.
01:13
So that means not defective is 99 % of the time.
01:21
Whereas supplier 2 or supplier b has a 2 % defective rate, which means that not defective is going to be 98 % and supplier c has a defective rate of 4%.
01:41
So that means they're not defective rate is 96%.
01:47
So that's your answer for part a where we had to construct the probability tree.
01:54
For part b we want to use this tree and we want to find a probability.
01:58
So for part b, you buy one of the components and when you try to use it, you find that the connector is defective.
02:10
And we want to know what's the probability that the component came from supplier a.
02:15
So we're looking for the probability of coming from supplier a, given that we know that it is defective.
02:23
So in this case, we are going to have to think about the formula for dependent probability.
02:33
And for dependent probability, the probability of event a, and then event b is equal to the probability of event a happening, multiplied by the probability of b happening given that we know that a has already occurred.
02:52
So our problem looks like this part of the formula.
02:57
So if i can isolate that part, i can then utilize the new formula to help us solve this problem.
03:05
So i'm going to divide by the probability of a on both sides.
03:12
So the probability of event b happening, given that a has already occurred, is equal to the probability of event a and event b happening divided by the probability of event a.
03:26
So in our scenario, our event a is our defective, and our event b is that.
03:38
That it's coming from supplier a.
03:42
So therefore, we could expand this out and say the probability of coming from supplier a and being defective divided by the probability of being defective.
03:54
So the probability of coming from a and defective will be these two multiplied together...