Question

7. According to the prostate cancer foundation, prostate cancer will strike 1 in 6 American men. Then the probability that an American man will develop prostate cancer is 1/6 = 0.167 . Assume that a random sample of 30 men was taken. Let X = number of american man develop prostate cancer. It should be noted that X has a binomial distribution with n = 30 and p = 0.167. P(X = x) = 30 C_x (0.167)^x (0.833)^{30-x}, x = 0, 1, 2, ..., 30. a. Find the probability that exactly five men from the sample will develop prostate cancer. Answer:

          7. According to the prostate cancer foundation, prostate cancer will strike 1 in 6
American men. Then the probability that an American man will develop prostate
cancer is 1/6 = 0.167 . Assume that a random sample of 30 men was taken.

Let X = number of american man develop prostate cancer.

It should be noted that X has a binomial distribution with n = 30 and
p = 0.167.

P(X = x) = 30 C_x (0.167)^x (0.833)^{30-x}, x = 0, 1, 2, ..., 30.

a. Find the probability that exactly five men from the sample will develop prostate
cancer.

Answer:

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7. According to the prostate cancer foundation, prostate cancer will strike 1 in 6
American men. Then the probability that an American man will develop prostate
cancer is 1/6 = 0.167 . Assume that a random sample of 30 men was taken.

Let X = number of american man develop prostate cancer.

It should be noted that X has a binomial distribution with n = 30 and
p = 0.167.

P(X = x) = 30 Cx (0.167)^x (0.833)^30-x, x = 0, 1, 2, ..., 30.

a. Find the probability that exactly five men from the sample will develop prostate
cancer.

Answer:

Added by Esther M.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Manisha Sarker

10/07/2023

Step 1

167. We want to find P(X = 5), which represents the probability that exactly five men from the sample will develop prostate cancer. Using the binomial probability formula, we have: P(X = 5) = (30 C 5) (0.167)^5 (0.833)^25 where (30 C 5) represents the number of Show more…

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According to the Prostate Cancer Foundation, prostate cancer will strike 1 in 6 American men. Therefore, the probability that an American man will develop prostate cancer is 0.167. Assume that a random sample of 30 men was taken. Let X be the number of American men who develop prostate cancer. It should be noted that X has a binomial distribution with n = 30 and p = 0.167. P(X = x) = 30C(x) * (0.167)^x * (0.833)^(30-x), where x = 0, 1, 2, ..., 30. a. Find the probability that exactly five men from the sample will develop prostate cancer. Answer:

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