00:01
All right, we need to balance the equation in potassium hydroxide, so in a basic solution.
00:06
And the first thing you need to do for that is to eliminate any spectator ions.
00:11
The potassium is going to be your spectator ion because group one metals are completely soluble.
00:18
Then you want to go ahead and split it into two half reactions.
00:21
We have the c3h802, yielding c3h204, and that have had.
00:30
A charge of two negative because we got rid of the two potassium.
00:35
Your other half reaction is the kmn -o -4.
00:38
We want to get rid of the k.
00:40
So m -n -o -4 negative yielding mn -o -2 on the product side.
00:49
Now we have our half reactions.
00:50
You're going to balance any atoms that are not oxygen or hydrogen.
00:55
So the carbon here, three on both sides, that's good.
00:58
Mangonies, one on both sides, you're good.
01:00
After you check that, then you will balance oxygens.
01:04
You can balance oxygens by adding water.
01:07
So we have two oxygens, four oxygens.
01:09
I need to add two waters to this side of the equation.
01:14
It's a weird looking each two waters.
01:17
And then on the product side for here, i need to also add two waters because i need to make the oxygens equal.
01:27
For the next step, then you will balance the hydrogens using hydrogen ions.
01:34
So we have 12 hydrogens altogether on this side and we only have two on the product side.
01:43
So that means i need to add in 10 hydrogen ions to the product side.
01:51
For our other half reaction i have four hydrogens on the product side so i need to add in four hydrogen ions on the reactants side.
02:02
Next thing you're going to do with those half reactions is balance the charge, and you'll do that using electrons.
02:09
So on the reactant side, i have a charge of zero right now, and on the product side, i have a charge of positive 8, so a negative 2 from the ion, and then positive 10 from the hydrogen, so have a plus 8 charge on the product side.
02:26
I need to balance that out by adding in 8 electrons on the product side, so that way they're both equal to zero.
02:38
On the other reaction, i have a charge of positive three on the reactant side and zero on the product side.
02:52
So in order to get that to balance out, i need to add in three electrons on the reactant side to make that work...