7. Calculate the pH of a 0.01 M solktion of salicylic acid which has a \( \mathrm{K}_{\mathrm{a}}=1.06 \times 10^{-3} \) at \( 25^{\circ} \mathrm{C} \). A. 2.25 . Bye.37. (C.) 2.56 . D. 2.85 . \[ =\sqrt{k_{G} c} \]
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01 \, \text{M} \) - Acid dissociation constant, \( K_a = 1.06 \times 10^{-3} \) Show more…
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