7) Charge \( Q_{1} \) is located 5.0 m from charge \( Q_{2} \) as shown. How much work must be done to move charge \( Q_{1} 2.0 \mathrm{~m} \) closer to charge \( Q_{2} \) ? \[ Q=2.0 \times 10^{-4} \mathrm{C} \] \[ Q_{1}=5.0 \times 10^{-6} \mathrm{C} \] ( + ( \( \ddagger \) 2.0 m 5.0 m
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- Initial distance, \( r_i = 5.0 \, \text{m} \) - Final distance, \( r_f = 3.0 \, \text{m} \) (since \( Q_1 \) is moved 2.0 m closer) Show more…
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