00:01
Now given that the q1 is equal to 2 .20 rc which is equals to 20 multiplied by 10x to minus 9c.
00:15
Similarly qt is equal to minus 20 multiplied by 10 to power minus 9 column.
00:22
Qt is equal to 10 multiplied by 10 to power minus 9 column.
00:27
2 .4 is equal to 40 multiplied by 10th of minus 9 fulam.
00:34
Now r13 is equal to 4 cm, which is equivalent to 0 .04 meter.
00:43
Similarly, r12 is equals to 4 .5 plus 4 cm which is equal to 8 .5 centimeters, which is equivalent to 0 .08 meter.
00:59
Now r23 is equal to 4 cm which is equivalent to 0 .04 meter.
01:07
Now the potential energy of configuration is u equals to k q1 q2 divided by r12 plus k k q1 3 divided by r13 plus k q222 divided by r13 plus k q222 divided by r2 3 on putting the values we get 2 is equal to 9, multiplied by tendous to power 9 in the bracket 20 multiplied by tendous to power minus 9 multiplied by minus 20 multiplied by tendous to power minus 9 all divided by 0 .08 plus 20 multiplied by tenderst to power minus 9.
02:03
Multiplied by 10, multiplied by 10x to power minus 9, all divided by 0 .04 plus minus 20, multiplied by 10, multiplied by 10 minus 9, divided by 0 .04.
02:25
Therefore, on solving, we get, u, that is, electric potential energy of configuration is equal to minus 4 .0.
02:34
09 multiplied by temperature 2 power 5 minus 5 joules.
02:40
Now for the 8th part, if we put a chart q4, then the initial potential energy on q4 is ui, which is equals to kq1, q4 divided by r1 4 plus k q2, q4 divided by r1 4 plus k q2, r2 4 plus k q3, q4 divided by r34.
03:13
Therefore ui is equal to taking kq4 as common, we have q1 divided by r1 4 plus q2 divided by r24 plus q3 divided by r34.
03:34
Now we have r14 is equal to.
03:39
To under root 3 square plus 4 square which is equals to 0 .05 meter...