7 mercury manometer level responds to the pressure drop...

7. Mercury manometer level responds to the pressure drop between its two legs with a second order process. If the response of the manometer to a unit step change in the pressure drop is such that we observe a small decay ratio in this step response. State and argue if this (small decay ratio) is a desirable response or not? 8. For Y(s)/X(s)=1/(s^2+

An inclined manometer is a useful device for measuring small pressure differences. The formula given in Section 3.4 for the pressure difference in terms of the liquid-level difference $h$ remains valid, but while $h$ would be small and difficult to read for a small pressure drop if the manometer were vertical, $L$ can be made quite large for the same pressure drop by making the angle of the inclination, $\theta,$ small. (a) Derive a formula for $h$ in terms of $L$ and $\theta$ (b) Suppose the manometer fluid is water, the process fluid is a gas, the inclination of the manometer is $\theta=15^{\circ},$ and a reading $L=8.7 \mathrm{cm}$ is obtained. What is the pressure difference between points? and?? (c) The formula you derived in Part (a) would not work if the process fluid were a liquid instead of a gas. Give one definite reason and another possible reason.

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