Question

7. (10 points) The loop gain of a three-pole amplifier is given by: $T(f) = \frac{250}{(1 + j\frac{f}{10^5})(1 + j\frac{f}{10^5})^2}$ (a) Show that the system is unstable. (b) Stabilize the circuit by moving the first pole at $f_{p1} = 10^3 Hz$ by introducing a compensation capacitor. Assume the other two poles remain fixed. (c) At what frequency the first pole must be moved to achieve a phase margin of 50 degrees?

          7. (10 points) The loop gain of a three-pole amplifier is given by:
$T(f) = \frac{250}{(1 + j\frac{f}{10^5})(1 + j\frac{f}{10^5})^2}$
(a) Show that the system is unstable.
(b) Stabilize the circuit by moving the first pole at $f_{p1} = 10^3 Hz$ by introducing a compensation
capacitor.
Assume the other two poles remain fixed.
(c) At what frequency the first pole must be moved to achieve a phase margin of 50 degrees?

7. (10 points) The loop gain of a three-pole amplifier is given by:
T(f) = (250)/((1 + j(f)/(10^5))(1 + j(f)/(10^5))^2)
(a) Show that the system is unstable.
(b) Stabilize the circuit by moving the first pole at fp1 = 10^3 Hz by introducing a compensation
capacitor.
Assume the other two poles remain fixed.
(c) At what frequency the first pole must be moved to achieve a phase margin of 50 degrees?

Added by Brian M.

University Physics with Modern Physics

Hugh D. Young 13th Edition

Chapter 30

Instant Answer

Solved by Expert Vivek K

Step 1

The loop gain is given by 250 * T(f), where T(f) is the transfer function of the amplifier. The loop gain can be written as: 250 * T(f) = 1 + j1 + 11 To determine the stability, we need to find the magnitude and phase of the loop gain. Let's calculate Show more…

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7. (10 points) The loop gain of a three-pole amplifier is given by: 250 * T(f) = 1 + j1 + 11 a) Show that the system is unstable. b) Stabilize the circuit by moving the first pole at fpi = 103Hz by introducing a compensation capacitor. Assume the other two poles remain fixed. c) At what frequency must the first pole be moved to achieve a phase margin of 50 degrees?