00:01
Hello students, in this question we have to evaluate the following integrals.
00:04
Here the first integral is 5x square plus 1 by x power 4 plus 2 into dx.
00:13
Here we can rewrite this as 5 into integral x square dx plus integral 1 by x power 4 into dx plus 2 into integral dx.
00:26
By integrating x square we will get x cube by 3 plus by integrating 1 by x power 4 we will get minus 1 by 3 x cube plus 2 into x plus c.
00:41
Therefore, the integral 5 x square plus 1 by x power 4 plus 2 into dx is 5 by 3 x cube minus 1 by 3 x cube plus 2 x plus c.
01:00
Next we have to evaluate the integral cos 3x plus e power 4x into dx.
01:11
Here we can write this as integral cos 3x into dx plus integral e power 4x into dx.
01:21
By integrating cos dx we will get sin 3x by 3 plus by integrating e power 4x we will get 1 by 4 into e power 4x plus integration constant c.
01:35
Therefore, integral of cos 3x plus e power 4x into dx equal to sin 3x by 3 plus e power 4x by 4 plus.
01:55
Next we have to evaluate the integral cos of lon x by x into dx.
02:05
Here we have to consider u equal to lon x.
02:12
Therefore, du becomes 1 by x into dx.
02:16
Therefore, the integration becomes integral of cos of lon x by x into dx equal to integral cos u into du.
02:31
By integrating cos u we will get sin u plus constant c.
02:36
Here we have to replace u by lon x.
02:39
Therefore, it will be sin of lon x plus c...