00:01
In our question we are given two blocks of masses m1 and m2 that are connected by a massless string that passes over a massless pulley.
00:07
The mass m2 which has a mass of 20 kg rests on a long ramp of angle 30 degrees.
00:12
Now the friction can be ignored in our given problem.
00:15
We first need to determine the value of mass m1 for which the two blocks are in equilibrium.
00:21
Now from the free body diagram of our system for mass m2 we have tension to be equal to.
00:33
Let this be equation 1.
00:34
And for mass m1 we have t to be equal to m1 g let this be equation 2.
00:42
Equating equation 1 and 2 we get giving us, substituting the values we get, the value of mass m1 to be equal to 10 kgis respectively.
01:08
Now in our next case we have been asked that if the actual mass of m1 is 5 kg and the system is allowed to move, what will be the magnitude of the acceleration of the two blocks.
01:16
Now here if mass m1 is equivalent to 5 kgues, therefore we'll use summation of forces for the mass m1 to be equivalent to the product of mass into acceleration.
01:28
Here we get t minus m1g to be equal to m1a giving us t equivalent to m1a plus m1g...