Question

Among 20 golden hamster litters recorded, there was a sample mean of \( \bar{x} = 7.72 \) baby hamsters, with a sample standard deviation of \( s = 2.5 \) hamsters per liter. Create a 98% confidence interval for the mean number of baby hamsters per liter. 7.72 \pm 2.50 7.72 \pm 0.5590 7.72 \pm 1.4196 7.72 \pm 1.2325 7.72 \pm 1.3005 None of the above

          Among 20 golden hamster litters recorded, there was a sample mean of \( \bar{x} = 7.72 \) baby hamsters, with a sample standard deviation of \( s = 2.5 \) hamsters per liter. Create a 98% confidence interval for the mean number of baby hamsters per liter.
7.72 \pm 2.50
7.72 \pm 0.5590
7.72 \pm 1.4196
7.72 \pm 1.2325
7.72 \pm 1.3005
None of the above

Among 20 golden hamster litters recorded, there was a sample mean of x̅ = 7.72 baby hamsters, with a sample standard deviation of s = 2.5 hamsters per liter. Create a 98% confidence interval for the mean number of baby hamsters per liter.
7.72 ±2.50
7.72 ±0.5590
7.72 ±1.4196
7.72 ±1.2325
7.72 ±1.3005
None of the above

Added by Christopher J.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Madhur L

05/09/2023

Step 1

33 (from a t-distribution with 19 degrees of freedom for a 98% confidence level). Margin of error = 2.33 * (2.5 / sqrt(20)) = 2.33 * (2.5 / 4.47) = 1.30 Show more…

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7.72 ± 2.50 7.72 ± 0.5590 7.72 ± 1.4196 7.72 ± 1.2325 7.72 ± 1.3005 None of the above Among 20 golden hamster litters recorded, there was a sample mean of 7.72 baby hamsters, with a sample standard deviation of s = 2.5 hamsters per litter. Create a 98% confidence interval for the mean number of baby hamsters per litter: 7.72 ± 2.50 7.72 ± 0.5590 7.72 ± 1.4196 7.72 ± 1.2325 7.72 ± 1.3005 None of the above