00:01
Hi, in this question we have to find the net flow of momentum out of the control volume which is due to viscous flow.
00:08
First we have to use viscous flow.
00:12
So here the resultant force can be written as d by dt of mv where mv is the momentum.
00:19
So here the net force is due to body, due to pressure and due to viscosity.
00:25
Then in integral form we can write it as it is f integration of p dot ds plus volume integration of rho into fb into dv plus f viscous.
00:37
Then the net flow is given through the surface s, net flow through a surface of s is given by integration of s into rho v ds into v.
00:52
So rho v into ds into v.
00:55
Similarly we have, so we have momentum equation is given by, so momentum of the fluid in volume is given by it is d by dt of triple integration of volume into rho v dv.
01:11
Now on substituting all those equation in the force equation we have f is equal to it is dou by dou t of triple integration of volume into rho v dv plus double integration of s into rho v ds v to v which is equal to minus of triple integration or double integration of p ds into triple integration of v rho fb into dv plus f viscous.
01:40
Then in the second part we have to use energy equation.
01:45
So energy equation and find the integral form.
01:49
Now by principle of conservation of energy, so conservation of energy we have t delta q plus delta w is equal to de...