Question

What is ( K_{P} ) at ( 1269^{circ} mathrm{C} ) for the reaction, if ( K_{c} ) is ( 3.8 imes 10^{-15} ) at the same temperature? [ 2 mathrm{CO}_{2}(g) ightleftharpoons 2 mathrm{CO}(g)+mathrm{O}_{2}(g) ] Round your answer to 2 significant digits. [ K_{P}= ]

          What is ( K_{P} ) at ( 1269^{circ} mathrm{C} ) for the reaction, if ( K_{c} ) is ( 3.8 	imes 10^{-15} ) at the same temperature?
[
2 mathrm{CO}_{2}(g) 
ightleftharpoons 2 mathrm{CO}(g)+mathrm{O}_{2}(g)
]
Round your answer to 2 significant digits.
[
K_{P}=
]
        
Show more…
What is ( KP ) at ( 1269^circ mathrmC ) for the reaction, if ( Kc ) is ( 3.8 	imes 10^-15 ) at the same temperature?
[
2 mathrmCO2(g) 
ightleftharpoons 2 mathrmCO(g)+mathrmO2(g)
]
Round your answer to 2 significant digits.
[
KP=
]

Added by Isabella G.

Close

Chemistry
Chemistry
Julia Burdge 1st Edition
Chapter 15
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Close icon
Play audio
Feedback
Powered by NumerAI
Kathleen Carty Danielle Fairburn
David Collins verified

Sima Sarker and 68 other subject Chemistry 102 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
what-is-k_p-at-1273circ-mathrmc-for-the-reaction-2-mathrmcogmathrmo_2g-rightleftarrows-2-mathrmco_2g

What is $K_{P}$ at $1273^{\circ} \mathrm{C}$ for the reaction $$2 \mathrm{CO}(g)+\mathrm{O}_{2}(g) \rightleftarrows 2 \mathrm{CO}_{2}(g)$$ if $K_{c}$ is $2.24 \times 10^{22}$ at the same temperature?

Chemistry

at-298-mathrmk-k_mathrmp-is-16-times-10-6-for-the-reaction-2-mathrmnoclg-rightleftharpoons-2-mathrmn

At $298 \mathrm{K}, K_{\mathrm{p}}$ is $1.6 \times 10^{-6}$ for the reaction 2 $\mathrm{NOCl}(g) \rightleftharpoons$ $2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g) .$ What is the value of $K_{\mathrm{c}}$ at this temperature?

 Chemistry

at-773circ-mathrmc-the-reaction-mathrmcog2-mathrmh_2g-rightleftharpoons-mathrmch_3-mathrmohg-has-k_m

At $773^{\circ} \mathrm{C}$ the reaction $\mathrm{CO}(g)+2 \mathrm{H}_{2}(g) \rightleftharpoons \mathrm{CH}_{3} \mathrm{OH}(g)$ has $K_{\mathrm{c}}=0.40$. What is $K_{\mathrm{P}}$ at this temperature?

Chemistry: The Molecular Nature of Matter


*

Recommended Textbooks

-
Chemistry: Structure and Properties

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition
achievement 1,695 solutions
Chemistry The Central Science

Chemistry The Central Science

Theodore L. Brown 14th Edition
achievement 1,954 solutions
Chemistry

Chemistry

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste 10th Edition
achievement 1,410 solutions

*

Transcript

-
00:01 Here in this problem this reaction is given and we have to find out the value for kp at 1269 degree celsius for this reaction and here the value for kc given 3 .8 times 10 to the power of negative 15 at the same temperature.
00:19 Here temperature given 1269 degree celsius we will convert to kelvin by adding 273 and we get 1542 kelvin.
00:36 Now we will find out delta n, delta n that is the number of moles of gaseous products minus number of moles of gaseous reactants.
00:45 Here 2 plus 1, 3 moles of gaseous products minus 2 moles of gaseous reactants...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever